I have recently been using the "roms_wilkin-master" toolkit. I would like to know how I should extract all the sea surface height data along the lon, lat paths.
So far I have found that the roms_genslice function can extract 4-D data along the path, but how should I get the zeta data?
How to extract all sea surface height data along the lon, lat path
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Re: How to extract all sea surface height data along the lon, lat path
I think you could use the roms_2d slice.m function in the same repository or use secondary software like Ferret (sample_xyt) to extract the data from the post-processed ROMS output data.
Re: How to extract all sea surface height data along the lon, lat path
Just code it yourself using the scatteredInterpolant class:
Code: Select all
% some ROMS output
f = 'http://tds.marine.rutgers.edu/thredds/dodsC/roms/doppio/2017_da/his/History_Best';
% get some zeta output
t0 = 1000;
tcount = 100;
zeta = ncread(f,'zeta',[1 1 t0],[Inf Inf tcount]);
% get the lon/lat coordinates
lon = ncread(f,'lon_rho');
lat = ncread(f,'lat_rho');
% construct a scatteredInterpolant class - do this only once because
% lon_rho,lat_rho don't change on subsequent uses of F
tindex = 1;
data = squeeze(zeta(:,:,tindex));
F = scatteredInterpolant(lon(:),lat(:),data(:));
% define the lon,lat path you want to "slice"
N = 100;
lontrk = linspace(-72.5,-70.5,N);
lattrk = linspace(40.0,36.5,N);
% Demo: step through the subset of zeta you downloaded and plot along
% the lon,lat path
for tindex = 1:tcount
% no need to recompute the scatteredInterpolant for every zeta, just
% update the Values
data = squeeze(zeta(:,:,tindex));
F.Values = data(:);
% evalute along lontrk,lattrk
dattrk = F(lontrk,lattrk);
% plot
plot(lontrk,dattrk)
ylim([-1 1])
drawnow
end
John Wilkin: DMCS Rutgers University
71 Dudley Rd, New Brunswick, NJ 08901-8521, USA. ph: 609-630-0559 jwilkin@rutgers.edu
71 Dudley Rd, New Brunswick, NJ 08901-8521, USA. ph: 609-630-0559 jwilkin@rutgers.edu
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Re: How to extract all sea surface height data along the lon, lat path
Thank you very much for your guidance, it has helped me a lot